Chemistry - Chemical Kinetics Question with Solution | TestHub

$\mathrm{t}=\frac{0.693}{\mathrm{k}}$for first order reaction
$\mathrm{k}=\frac{2.303}{\mathrm{t}\mathrm{i}\mathrm{m}\mathrm{e}}\log \left(\frac{\mathrm{a}}{\mathrm{a}-\mathrm{x}}\right)$
$\frac{\text{0}\text{.693}}{{\text{t}}_{\text{1/2}}}\text{=}\frac{\text{2}\text{.303}}{\text{time}}\text{log}\left(\frac{\text{100}}{\text{100}-\text{99}\text{.9}}\right)$
$\text{time}=\frac{6.903}{0.693}{\text{t}}_{\text{1/2}}\approx {\text{10t}}_{\text{1/2}}$