The rate constant for a second order reaction, A → Product is 1 ⋅ 62 M − 1 s − 1 . What will be the rate of reaction when concentration of reactant is 2 × 1 0 − 3 M ?

A ⟶ Product second order zeaction R = K [ A ] 2 ∴ K [ A ] R ⟶ Rate of Reaction R = 1.62 M − 1 S − 1 = 2 × 1 0 − 3 M = ? = ( 1.62 ) ( 2 × 1 0 − 3 ) 2 = 6.48 × 1 0 − 6 MS − 1

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ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

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The rate constant for a second order reaction, $A \to$ Product is $1 \cdot 62 M^{- 1} s^{- 1} .$ What will be the rate of reaction when concentration of reactant is $2 \times 1 0^{- 3} M ?$

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Solution:

A $⟶$ Product second order zeaction $R = K [A]^{2}$ $∴ K [A] R ⟶ Rate of Reaction R = 1.62 M^{- 1} S^{- 1} = 2 \times 1 0^{- 3} M = ? = (1.62) (2 \times 1 0^{- 3})^{2} = 6.48 \times 1 0^{- 6} MS^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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