Chemistry - Chemical Kinetics Question with Solution | TestHub

$1\times 10^{-3}=\mathrm{k}\left[0.05{]}^{\mathrm{\alpha }}\right[0.05{]}^{\mathrm{\beta }}$…(i)
$3\times 10^{-3}=\mathrm{k}\left[0.15{]}^{\mathrm{\alpha }}\right[0.05{]}^{\mathrm{\beta }}$…(ii)
$9\times 10^{-3}=\mathrm{k}\left[0.05{]}^{\mathrm{\alpha }}\right[0.15{]}^{\mathrm{\beta }}$…(iii)
From (i) and (ii),$\mathrm{\alpha }=1$
and from (i) and (iii),$\mathrm{\beta }=2$
So rate$=\mathrm{k}\left[\mathrm{N}\mathrm{O}{]}^2\right[\mathrm{C}{\mathrm{l}}_2{]}^1$.