The rate of reaction is expressed as 1 2 + d d t [ C ] = 1 3 - d d t [ D ] = 1 4 + d d t [ A ] = - d d t [ B ] , The reaction is

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ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

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The rate of reaction is expressed as

$\frac{1}{2} \frac{+ d}{d t} [C] = \frac{1}{3} \frac{- d}{d t} [D] = \frac{1}{4} \frac{+ d}{d t} [A] = - \frac{d}{d t} [B]$ ,

The reaction is

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Answer:

Solution:

Rate $= \frac{1}{2} \frac{d [C]}{d t} = \frac{1}{3} \frac{- d [D]}{d t} = \frac{1}{4} \frac{d [A]}{d t} = \frac{- d [B]}{d t}$
So Stoichiometric coefficient of B = 1
Stoichiometric coefficient of D = 3
Stoichiometric coefficient of A = 4
Stoichiometric coefficient of C = 2
Therefore, the reaction is B + 3D $\to$ 4A + 2C.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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