Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

In a reaction, the time required to complete half of the reaction was found to increase 16 times when the initial concentration of the reactant was reduced to 1/4th. What is the order of the reaction?

Answer:

3.00

Solution:

$\frac{t_{2}}{t_{1}} = {(\frac{a_{1}}{a_{2}})}^{n - 1}$
$16 = {(\frac{1}{1 / 4})}^{n - 1}$
So n = 3
i.e., third order reaction.

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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