Chemistry - Chemical Kinetics Question with Solution | TestHub

From the rate law:

$\text{log}\frac{-\mathrm{d}\left[\mathrm{A}\right]}{\mathrm{d}\mathrm{t}}=\mathrm{l}\mathrm{o}\mathrm{g}\frac{\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{d}\mathrm{t}}+0.3010=\log \frac{-\mathrm{d}\mathrm{A}}{\mathrm{d}\mathrm{t}}=\log \frac{\mathrm{d}\mathrm{B}}{\mathrm{d}\mathrm{t}}+\log 2$

$\frac{-\mathrm{d}\left[\mathrm{A}\right]}{\mathrm{d}\mathrm{t}}=2\times \frac{\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{d}\mathrm{t}}$

$2\mathrm{A}\to \mathrm{B}$ and we know $2{\mathrm{C}}_2{\mathrm{H}}_4\to {\mathrm{C}}_4{\mathrm{H}}_8$