Chemistry - Chemical Kinetics Question with Solution | TestHub

The nucleus ${}_{29}^{64}Cu$ accepts an orbital electron to yield ${}_{28}^{64}Ni$. The atomic number of $\mathrm{Cu}$ is 29 , which is equal to the number of electrons and also equal to the number of protons. When ${}_{29}^{64}Cu$ accepts an orbital electron then electrons subtract from the atomic number, i.e. $29-1=28$ $${}_{29}^{64}Cu+{}_{-1}{e}^0⟶{}_{28}^{64}\mathrm{Ni}$$