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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsHard2 minPYQ_2011

ChemistryHardsingle choice

2 g of a radioactive sample having half-life of 15 days was synthesised on 1st Jan 2009. The amount of the sample left behind on 1st March, 2009 (including both the days) is

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Answer:

Solution:

$N = N_{0} (\frac{1}{2})^{n}$ Given, $N_{0} = 2 g$ $t_{1/2} = 15$ days $t = 60$ days $\Rightarrow n = \frac{60}{15} = 4$ $∴ N = 2 (\frac{1}{2})^{4}$ or $N = 0.125 g$

Stream:JIPMERSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2011

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