Chemistry - Chemical Kinetics Question with Solution | TestHub

As the slowest step is the rate determining step, hence from step 2 ,
From step 1, $K_{eq}=\frac{\left[{\mathrm{O}}_2\right][\mathrm{O}]}{\left[{\mathrm{O}}_3\right]}$
From eq. (i) and (ii), $r=k{K}_{eq}\frac{{\left[{\mathrm{O}}_3\right]}^2}{\left[{\mathrm{O}}_2\right]}=k^{\prime }{\left[{\mathrm{O}}_3\right]}^2{\left[{\mathrm{O}}_2\right]}^{-1}\left[\because k^{\prime }=k{K}_{eq}\right]$