Acid hydrolysis of ester is first order reaction and rate constant is given by k = t 2.303 lo g V ∞ − V t V ∞ − V 0 where, V 0 , V t and V ∞ are the volumle of standard NaOH required

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Acid hydrolysis of ester is first order reaction and rate constant is given by k = t 2.303 ​ lo g V ∞ ​ − V t ​ V ∞ ​ − V 0 ​ ​ where, V 0 ​ , V t ​ and V ∞ ​ are the volumle of standard NaOH required to neutralise acid present at a given time, if ester is 50% neutralised then

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RCOOR ′ + H 2 ​ O ⟶ H + ​ RCOOH + R ′ OH At t = 0 , At timet, At time ∞ , At t = 0 , V 0 ​ = volume ​ a a − x a − a Va t ​ = x + V 0 ​ ​ 0 x a ​ 0 x a (catalyst) ​ V ∞ ​ = a + V 0 ​ If ester is 50% hydrolysed then, x = 2 a ​ or V t ​ = 2 a ​ + V 0 ​ or a = 2 V t ​ − 2 V 0 ​ ∴ V ∞ ​ = 2 V t ​ − 2 V 0 ​ + V 0 ​ = 2 V t ​ − V 0 ​ ​

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