Consider the following reaction, The reaction is of first order in each diagram, with an equilibrium constant of 1 0 4 . For the conversion of chair form to boat form e − E a / RT = 4.35 × 1 0 − 8 m a

Question

Consider the following reaction,
The reaction is of first order in each diagram, with an equilibrium constant of $1 0^{4}$ . For the conversion of chair form to boat form $e^{- E a / RT} =$ $4.35 \times 1 0^{- 8} m$ at $298 K$ with pre-exponential factor of $1 0^{12} s^{- 1}$ . Apparent rate constant $(= k A / k B)$ at $298 K$ is

TestHub · Accepted Answer

​ K B ​ = Ae − E a ​ / RT = 1 0 12 × 4.35 × 1 0 − 8 = 4.35 × 1 0 4 s − 1 ​ Also equilibrium constant, k = k B ​ k A ​ ​ = 1 0 4 ∴ k A ​ = k B ​ × 1 0 4 = 4.35 × 1 0 8 s − 1

Chemistry - Chemical Kinetics Question with Solution | TestHub

Options:

Doubts & Discussion