Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were 256 g, the mass of it in grams remaining undecayed after 18 hours would be:

Answer:

4.00

Solution:

$t_{1 / 2} = 3 hours, n = T / t_{1 / 2} = 18 / 3 = 6$

$N = N_{0} {(\frac{1}{2})}^{6}$
$= 256 \times \frac{1}{8} \times \frac{1}{8} = 4 g \cdot$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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