Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumDegree of Dissociation/Vapour Density/Molar MassHard2 minQB
ChemistryHardsingle choice
At 27°C, N2O4 dissociates as N2O4(g) ⇌ 2NO2(g). The equilibrium vapours are found to be 40 times as heavy as hydrogen. The percentage dissociation of N2O4 is
Options:
Answer:
C
Solution:
Molar mass of N2O4 = 92, so theoretical vapour density D = 46 Observed vapour density d = 40
α = (D-d)/(d(n-1)) = (46-40)/(40×1) = 0.15
Dissociation is 15%.
This is option (c).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Degree of Dissociation/Vapour Density/Molar Mass
⏱ 2mℹ️ Source: QB
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