For the dissociation A 2 B 3 ( g ) ⇌ 2 A B ( g ) + 2 1 B 2 ( g ) If, M = Molecular mass of A 2 B 3 ( g ) D = Vapor density of equilibrium mixture P ∘ = Initial pressure of A 2 B 3 ( g

Question

For the dissociation A 2 ​ B 3 ​ ( g ) ⇌ 2 A B ( g ) + 2 1 ​ B 2 ​ ( g ) If, M = Molecular mass of A 2 ​ B 3 ​ ( g ) D = Vapor density of equilibrium mixture P ∘ = Initial pressure of A 2 ​ B 3 ​ ( g ) then, identify the correct statement(s):

TestHub · Accepted Answer

α = ( n − 1 ) d 0 ​ d t ​ − d o ​ ​ = ( 2.5 − 1 ) D 2 M ​ − D ​ = 3 D M − 2 D ​ A 2 ​ B 3 ​ ( g ) ⇌ 2 AB ( g ) + 2 1 ​ B 2 ​ ( g ) 1 − ( 3 D M − 2 D ​ ) + 2 ( 3 D M − 2 D ​ ) + ( 6 D M − 2 D ​ ) = 1 + 2 D M − 2 D ​ P f ​ P ∘ ​ = 1 + 2 D M − 2 D ​ 1 ​ or P f ​ = 2 D P ∘ M ​

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