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ChemistryChemical EquilibriumProblems involving KcHard2 minQB

ChemistryHardsingle choice

For $2 I Cl (g) ⇌ I_{2} (g) + C l_{2} (g), K_{C} = 0.25$ . If initially 0.8 M $I Cl$ was taken, the equilibrium concentration of $I Cl$ is

Answer:

Solution:

Let $[I_{2}] = [C l_{2}] = x$ , $[I Cl] = 0.8 - 2 x$ .

$x^{2} / (0.8 - 2 x)^{2} = 0.25$ , so $x / (0.8 - 2 x) = 0.5$ , which gives $x = 0.4 - x$ , so $x = 0.2$ .

$[I Cl] = 0.8 - 0.4 = 0.4 M$ .

Trap: 0.2 M is $[I_{2}]$ .

Answer: (A).

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc

⏱ 2mℹ️ Source: QB

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