Chemistry - Chemical Equilibrium Question with Solution | TestHub

$\underset{\underset{0.03\mathrm{M}}{\mathrm{T}=00}}{\mathrm{A}\mathrm{g}(\mathrm{C}\mathrm{N}{)}_2^{-}}\rightleftharpoons \underset{\underset{\underset{\left(\mathrm{v}\mathrm{e}\mathrm{r}\mathrm{y}\mathrm{s}\mathrm{m}\mathrm{a}\mathrm{l}\mathrm{l}\right)}{\mathrm{x}\mathrm{M}}}{}}{\mathrm{A}{\mathrm{g}}^{+}}+\underset{\underset{}{0.1-0.03\times 2}}{2\mathrm{C}{\mathrm{N}}^{-}}$
${\text{K}}_{\text{p}}\text{=}\frac{\left({\text{Ag}}^{\text{+}}\right){{\text{(CN}}^{-}\text{)}}^{\text{2}}}{{{\text{[Ag(CN)}}_{\text{2}}\text{]}}^{-}}$
$\frac{\mathrm{x}(0.04{)}^2}{0.03}=4\times 10^{-19}$
On solving$\mathrm{x}=7.5\times 10^{-18}\mathrm{M}$