Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumDegree of Dissociation/Vapour Density/Molar MassMedium2 minQB

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At 2 atm total pressure, $PC l_{5}$ is 40% dissociated into $PC l_{3}$ and $C l_{2}$ . Then $K_{p}$ is

Answer:

Solution:

$PC l_{5} ⇌ PC l_{3} + C l_{2} : K_{P} = α^{2} P / (1 - α^{2})$ .

$K_{P} = (0.16) (2) / (0.84) = 0.38 atm$ .

Answer: (A).

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Degree of Dissociation/Vapour Density/Molar Mass

⏱ 2mℹ️ Source: QB

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