Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KpEasy2 minQB
ChemistryEasysingle choice
Methanol, CH3OH can be prepared from CO and H2 as
CO(g) + 2H2(g) ⇌ CH3OH(g); Kp = 1.0 × 10-2 at 500 K.
What total pressure is required to convert 50% of CO to CH3OH at 500 K, if CO and H2 come from the reaction:
CH4(g) + H2O(g) → CO(g) + 3H2(g)
Options:
Answer:
C
Solution:
Start with CO = 1, H2 = 3 mol; 50% conversion gives CO = 0.5, H2 = 2.0, CH3OH = 0.5; total = 3.0 mol Mole fractions: CO = 1/6, H2 = 2/3, CH3OH = 1/6
Kp = (P/6)/[(P/6)(2P/3)2] = 9/(4P2)
P2 = 9/(4 × 1.0 × 10-2) = 225 gives P = 15 bar
This is option (c).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp
⏱ 2mℹ️ Source: QB
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