The rate constant for the forward reaction A(g) ⇌ 2B(g) is 4.0×10 -3 s -1 at 400 K. At equilibrium a 20 L vessel contains 2.0×10 -4 moles of A and 40 moles of B. The rate constant of the backward reac

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The rate constant for the forward reaction A(g) ⇌ 2B(g) is 4.0×10 -3 s -1 at 400 K. At equilibrium a 20 L vessel contains 2.0×10 -4 moles of A and 40 moles of B. The rate constant of the backward reaction at this temperature is

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[A] = 2.0×10 -4 /20 = 1.0×10 -5 M and [B] = 40/20 = 2 M K c = ([B] 2 )/([A]) = ((2) 2 )/(1.0×10 -5 ) = 4.0×10 5 M k b = k f /K c = (4.0×10 -3 )/(4.0×10 5 ) k b = 1.0×10 -8 M -1 s -1 This is option (d).

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