Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The vapour pressure of mercury is 0.002 mm Hg at $27 ° C$
$H g (l) ⇌ H g (g)$
The value of equilibrium constant $K_{C}$ is

Options:

Answer:

Solution:

$H g (l) ⇌ H g (g)$
$Δ n_{g} = 1$
$K_{p} = \frac{0.002}{760} = 2.63 \times 1 0^{- 6}$ atm
$K_{p} = K_{c} (R T)^{Δ n}$
$K_{c} = \frac{K_{p}}{R T} = \frac{2.63 \times 1 0^{- 6}}{0.0821 \times 300}$
$= 1.068 \times 1 0^{- 7}$ M

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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