Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumDegree of Dissociation/Vapour Density/Molar MassMedium2 minQB
ChemistryMediumsingle choice
What is the common degree of dissociation in the two initially pure gas experiments?
Options:
Answer:
D
Solution:
For initially pure NOCl, equilibrium mole amounts are 1-α, α and α/2. Kp/P = α3/[(2+α)(1-α)2] = 1/5.
5α3 = (2+α)(1-α)2, giving 4α3+3α-2 = 0.
The value α = 0.50 satisfies this equation; its left-hand side increases throughout the physical interval, so this root is unique.
The common degree of dissociation is 0.50, option (d).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Degree of Dissociation/Vapour Density/Molar Mass
⏱ 2mℹ️ Source: QB
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