For the reaction A ( g ) ⇌ B ( g ) , the equilibrium partial pressures of gases A and B are 4 atm . and 2 atm . respectively. If equilibrium mixture is slowly and isothermally compressed to 12 atm .

Question

For the reaction A ( g ) ​ ⇌ B ( g ) , the equilibrium partial pressures of gases A and B are 4 atm . and 2 atm . respectively. If equilibrium mixture is slowly and isothermally compressed to 12 atm ., maintaining equilibrium, then the new equilibrium pressure (in atm .) of B ( g ) is

TestHub · Accepted Answer

A ( g ) ​ ⇌ B ( g ) ​ ; K P ​ = 4 2 2 ​ = 1 atm At new equilibrium, Let p.p of A ( g ) = x atm , and p.p of B ( g ) = y atm . Then, total pressure = ( x + y ) = 12 atm . K P ​ = x y 2 ​ = 1 ; solving gor x and y , we get p.p.of B ( g ) ​ = 3 atm

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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