Following equilibria are established on mixing two gases A 2 and C: 3A 2 (g) ⇌ A 6 (g); K P = 0.8 atm -2 A 2 (g) + C(g) ⇌ A 2 C(g); K P = 'x' atm -1 When A 2 (g) and C(g) are mixed in 2:1 mo

Question

Following equilibria are established on mixing two gases A₂ and C:

3A₂(g) ⇌ A₆(g); K_P = 0.8 atm^-2

A₂(g) + C(g) ⇌ A₂C(g); K_P = 'x' atm^-1

When A₂(g) and C(g) are mixed in 2:1 molar ratio, the total pressure of gases at equilibrium is found to be 1.2 atm and the partial pressure of A₆(g) is 0.1 atm. The value of 'x' is

TestHub · Accepted Answer

K P = P A6 /P A2 3 = 0.1/P A2 3 = 0.8 P A2 3 = 0.125, so P A2 = 0.5 atm Let the initial pressures (no reaction) be A 2 = 2p and C = p P C + P A2C = p (C is conserved between free C and A 2 C) Total pressure = 0.5 + 0.1 + p = 1.2, so p = 0.6 atm A 2 balance: 2(0.6) = 0.5 + 3(0.1) + P A2C , so P A2C = 0.4 atm P C = 0.6 - 0.4 = 0.2 atm x = 0.4/[(0.5)(0.2)] x = 4

Chemistry - Chemical Equilibrium Question with Solution | TestHub

Doubts & Discussion