Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumDegree of Dissociation/Vapour Density/Molar MassMedium2 minQB

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For the dissociation $PC l_{5} (g) ⇌ PC l_{3} (g) + C l_{2} (g)$ , the degree of dissociation $(α)$ in terms of $K_{p}$ and total equilibrium pressure $P$ is

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Answer:

Solution:

$K_{p} = α^{2} P / (1 - α^{2})$ .

$K_{p} - K_{p} α^{2} = P α^{2}$ , so $α^{2} = K_{p} / (K_{p} + P)$ .

$α = K_{p} / (K_{p} + P)$ . (The factor $4 P$ belongs to $N_{2} O_{4}$ .)

Answer: (B).

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Degree of Dissociation/Vapour Density/Molar Mass

⏱ 2mℹ️ Source: QB

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