Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumProblems involving KcMedium2 minPYQ_2021

ChemistryMediumnumerical

For the reaction

$A + B ⇌ 2 C$

the value of equilibrium constant is $100$ at $298 K$ . If the initial concentration of all the three species is $1 M$ each, then the equilibrium concentration of $C$ is $x \times 10^{- 1} M$ . The value of $x$ is _______. (Nearest integer)

Answer:

25.00

Solution:

$K = \frac{{[C]}_{eq}^{2}}{{[A]}_{eq} {[B]}_{eq}} = \frac{{(1 + 2 x)}^{2}}{(1 - x) (1 - x)}$

$100 = {(\frac{1 + 2 x}{1 - x})}^{2}$

$(\frac{1 + 2 x}{1 - x}) = 10$

$x = \frac{3}{4}$

$[C] e_{q .} = 1 + 2 x$

$= 1 + 2 (\frac{3}{4})$

$= 2.5 M$

$= 25 \times 10^{- 1} M$

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc

⏱ 2mℹ️ Source: PYQ_2021

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