Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KcHard2 minQB
ChemistryHardsingle choice
Carbon monoxide in water gas reacts with steam according to the reaction:
CO(g) + H2O(g) ⇌ CO2(g) + H2(g); Keq = 0.60
If two volumes of water gas (containing 1:1 of CO and H2) are mixed with three volumes of steam, then the volume ratio CO : H2O : CO2 : H2 at equilibrium is
Options:
Answer:
A
Solution:
Initial volumes: CO = 1, H2 = 1, H2O = 3 Let x volume of CO react: CO = 1 - x, H2O = 3 - x, CO2 = x, H2 = 1 + x
Δ ng = 0, so K = x(1+x)/[(1-x)(3-x)] = 0.60
x + x2 = 0.6(3 - 4x + x2) gives 0.4x2 + 3.4x - 1.8 = 0, that is 2x2 + 17x - 9 = 0
x = (-17 + 19)/4 = 0.5
CO : H2O : CO2 : H2 = 0.5 : 2.5 : 0.5 : 1.5 = 1 : 5 : 1 : 3
This is option (a).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB
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