Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumLe-Chatelier's PrincipleMedium2 minQB
ChemistryMediummatching list

Match each reaction in Column I with the effect of adding water in Column II (reactions in aqueous solution; is left out of ) (a Column I entry may match more than one Column II entry):

Column I (Reaction)

Column II (Effect on addition of water)

(P)

(1) Moles of A increases

(Q)

(2) Moles of B increases

(R)

(3) Molar concentration of A decreases

(S)

(4) Molar concentration of B decreases

Choose the option with the correct matching:

Options:

Answer:
C
Solution:

Dilution by a factor d divides every concentration by d, so concentrations of A and B always fall (3, 4). Then compare with .

(P) : is unchanged, no shift: (3, 4).

(Q) : becomes , forward: moles of B increase (2, 3, 4).

(R) : becomes , backward: moles of A increase (1, 3, 4).

(S) : becomes , forward: (2, 3, 4).

Correct matching: P to 3,4; Q to 2,3,4; R to 1,3,4; S to 2,3,4. Answer: (C).

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Le-Chatelier's Principle
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...