NH 4 HS(s) decomposes as NH 4 HS(s) ⇌ NH 3 (g) + H 2 S(g) with K p = 0.0975 atm 2 . NH 3 at 0.60 atm and H 2 S at 0.10 atm are introduced into an evacuated vessel containing excess solid NH 4 HS. The

Question

NH 4 HS(s) decomposes as NH 4 HS(s) ⇌ NH 3 (g) + H 2 S(g) with K p = 0.0975 atm 2 . NH 3 at 0.60 atm and H 2 S at 0.10 atm are introduced into an evacuated vessel containing excess solid NH 4 HS. The total pressure after a long time is

TestHub · Accepted Answer

Initial Q p = (0.60)(0.10) = 0.060 atm 2 < K p , so the solid decomposes further Let each gas rise by x: (0.60+x)(0.10+x) = 0.0975 x 2 + 0.70x - 0.0375 = 0, so x = 0.05 atm P total = (0.60+0.05) + (0.10+0.05) = 0.80 atm This is option (a).

Chemistry - Chemical Equilibrium Question with Solution | TestHub

Options:

Doubts & Discussion