Chemistry - Chemical Equilibrium Question with Solution | TestHub

Adding the two reactions gives ${\mathrm{N}}_2+2{\mathrm{O}}_2\rightleftharpoons 2\mathrm{N}{\mathrm{O}}_2$ with K = $K_1{K}_2=4\times 10^{-31}\times 6\times 10^{12}=2.4\times 10^{-18}$.

The required equation is half of this, so K = $\sqrt{2.4\times 10^{-18}}=1.55\times 10^{-9}$.

Trap: $2.4\times 10^{-18}$ is the constant for the full equation.

Answer: (A).