The dissociation equilibrium of a gas AB 2 can be represented as, 2 AB 2 ( g ) ⇌ 2 AB ( g ) + B 2 ( g ) . The degree of dissociation is ' x ' and is small compared to 1. The expression

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The dissociation equilibrium of a gas AB 2 ​ can be represented as, 2 AB 2 ​ ( g ) ⇌ 2 AB ( g ) + B 2 ​ ( g ) . The degree of dissociation is ' x ' and is small compared to 1. The expression relating the degree of dissociation ( x ) with equilibrium constant K P ​ and total pressure P isNEET 2008 (Mains)

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​ 2 AB 2 ​ ⇌ 2 AB + B 2 ​ 1 00 1 − x x x /2 ​ Total mole at equi. = 1 + 2 x ​ ∴ K P ​ = ( 1 + x /2 1 − x ​ × P ) 2 ( 1 + x /2 x ​ × P ) 2 ( 1 + x /2 x /2 ​ × P ) ​ (Here x is degree of dissociation) or K P ​ = 2 x 3 P ​ or x 3 = P 2 K P ​ ​ or x = ( P 2 K P ​ ​ ) 1/3

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