Chemistry - Chemical Equilibrium Question with Solution | TestHub
Match Column I with Column II
Column I (Reactions) Column II (Effect on addition of water)
Column I | Column II |
|---|---|
P) A(aq) + H2O(l) ⇌ 2B(aq) | i) Moles of 'A' increases |
Q) 3B(aq) ⇌ 2A(aq) | ii) Moles of 'B' increases |
R) 2B(aq) ⇌ 3A(aq) | iii) Molar concentration of 'A' decreases |
S) 2A(aq) + H2O(l) ⇌ B(aq) | iv) Molar concentration of 'B' decreases |
Options:
Answer:
Solution:
Adding water dilutes every aqueous species, causing each concentration to fall instantly upon mixing. The equilibrium then shifts toward the side with more dissolved particles.
For reaction P, particles go 1 to 2, so the shift is forward. Moles of B increase (ii). The concentration of A, [A], falls due to dilution (iii), and the concentration of B, [B], also ends up lower than before the addition (iv).
For reaction Q, particles go 3 to 2 on the forward side, so dilution shifts it backward. Moles of B increase (ii). The concentration of A, [A], decreases (iii), and the concentration of B, [B], decreases (iv).
For reaction R, particles go 2 to 3, so the shift is forward. Moles of A increase (i). The concentration of A, [A], decreases (iii), and the concentration of B, [B], decreases (iv).
For reaction S, particles go 2 to 1, so the shift is backward. Moles of A increase (i). The concentration of A, [A], decreases (iii), and the concentration of B, [B], decreases (iv).
The correct mapping is option (d).
