Match Column I with Column II for the reaction: 2A(g) ⇌ 3B(g) + C(s); Δ H = -ve Column I Column II P) Increase in total pressure at equilibrium i) Increase in moles of A Q) Increase in volume at

Question

Match Column I with Column II for the reaction: 2A(g) ⇌ 3B(g) + C(s); Δ H = -ve ​ Column I Column II P) Increase in total pressure at equilibrium ​ i) Increase in moles of A ​ Q) Increase in volume at equilibrium ​ ii) Increase in moles of B ​ R) Addition of He(g) at constant pressure ​ iii) Increase in moles of C ​ S) Increase in temperature at constant volume ​ iv) Increase in molar concentration of A ​ v) Increase in molar concentration of B ​

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Δ n g ​ = 3 - 2 = +1 and the forward reaction is exothermic P: raising the total pressure by compression shifts the equilibrium backward, so moles of A increase (i); compression raises every gas concentration and the partial back-shift only reduces the rise, so [A] increases (iv) and [B] also increases (v) Q: increasing the volume shifts the equilibrium forward, so moles of B increase (ii) and moles of C increase (iii), while all gas concentrations fall R: adding He at constant pressure enlarges the volume, so again the forward shift gives (ii) and (iii) S: the reaction is exothermic, so raising the temperature shifts it backward; moles of A increase (i) and, the volume being fixed, [A] increases (iv), while moles and concentration of B decrease The correct mapping is option (b). ​

Column I	Column II
$P) Increase in total pressure at equilibrium$	$i) Increase in moles of A$
$Q) Increase in volume at equilibrium$	$ii) Increase in moles of B$
$R) Addition of He(g) at constant pressure$	$iii) Increase in moles of C$
$S) Increase in temperature at constant volume$	$iv) Increase in molar concentration of A$
	$v) Increase in molar concentration of B$

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