Chemistry - Chemical Equilibrium Question with Solution | TestHub

$$\begin{array}{c}\text{Take}\text{2}\text{mol}\text{NO}\text{and}\text{1}\text{mol}{\text{Cl}}_{\text{2}}\text{;}\text{let}\text{x}\text{mol}\text{of}{\text{Cl}}_{\text{2}}\text{react}\text{At}\text{equilibrium:}\text{NO}\text{=}\text{2}\text{-}\\ \text{2x,}{\text{Cl}}_{\text{2}}\text{=}\text{1}\text{-}\text{x,}\text{NOCl}\text{=}\text{2x}\\ \text{2x}\text{=}\text{(1}\text{-}\text{x)/4}\text{gives}\text{x}\text{=}\text{1/9}\\ \text{Moles:}\text{NO}\text{=}\text{16/9,}{\text{Cl}}_{\text{2}}\text{=}\text{8/9,}\text{NOCl}\text{=}\text{2/9;}\text{total}\text{=}\text{26/9}\text{mol}\\ \text{Partial}\text{pressures}\text{at}\text{1}\text{atm:}{\text{P}}_{\text{NO}}\text{=}\text{16/26,}{\text{P}}_{\text{Cl2}}\text{=}\text{8/26,}{\text{P}}_{\text{NOCl}}\text{=}\text{2/26}\\ {\text{K}}_{\text{p}}\text{=}{\text{(2/26)}}^{\text{2}}\text{/}{\text{[(16/26)}}^{\text{2}}\times \text{(8/26)]}\text{=}\text{13/256}{\text{atm}}^{\text{-1}}\\ \text{This}\text{is}\text{option}\text{(b).}\end{array}$$