Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumPhysical Equilibrium and Phase DiagramMedium2 minQB

ChemistryMediummultiple choice

In an acidic indicator $H I_{n}$ has ionisation constant is $1 0^{- 8}$ . The acid form of indicator is yellow and alkaline form is red. Which is correct statement (Given $lo g 2 = 0.3, lo g 3 = 0.48$ )

Options:(select one or more)

Answer:

A, B, C

Solution:

$P H_{1} = 8 + lo g \frac{25}{75} = 8 + lo g \frac{1}{3}$

$P H_{2} = 8 + lo g \frac{75}{25} = 8 + lo g 3$

Change in $P H = lo g 3 - lo g \frac{1}{3} = 2 lo g 3 = 2 \times 0.48 = 0.96$

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Physical Equilibrium and Phase Diagram

⏱ 2mℹ️ Source: QB

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