Chemistry - Chemical Equilibrium Question with Solution | TestHub

Formation of 0.20 mol ammonia consumes 0.10 mol nitrogen, leaving 0.20 mol nitrogen. The total equilibrium amount is PV/(RT)=(8.00)(4.926)/[(0.0821)(600)]=0.80 mol.

Hydrogen therefore has amount 0.80-0.20-0.20=0.40 mol.

Since RT/V=10.0 atm/mol, the partial pressures of nitrogen, hydrogen and ammonia are 2.00, 4.00 and 2.00 atm.

K_p=(2.00)²/[(2.00)(4.00)³]=0.03125 atm^-2.

This is option (d).