Column I gives reactions at 400 K ( R = 0.082 L atm mol − 1 K − 1 , so RT = 32.8 L atm m o l − 1 ). Match each reaction with the statements in Column II that are true for it (a Column I entry may matc

Question

Column I gives reactions at 400 K ( R = 0.082 L atm mol − 1 K − 1 , so RT = 32.8 L atm m o l − 1 ). Match each reaction with the statements in Column II that are true for it (a Column I entry may match more than one Column II entry): Column I (Reaction) Column II (Statement) (P) 2 N H 3 ​ ( g ) ⇌ N 2 ​ ( g ) + 3 H 2 ​ ( g ) (1) K P ​ / K C ​ = 32.8 (Q) N 2 ​ ( g ) + 3 H 2 ​ ( g ) ⇌ 2 N H 3 ​ ( g ) (2) K P ​ / K C ​ is about 1076 (R) 2 S O 3 ​ ( g ) ⇌ 2 S O 2 ​ ( g ) + O 2 ​ ( g ) (3) K P ​ / K C ​ = 1 (S) 2 NO ( g ) + O 2 ​ ( g ) ⇌ 2 N O 2 ​ ( g ) (4) K P ​ / K C ​ is about 0.0305 (5) K P ​ / K C ​ is about 9.3 × 1 0 − 4 (6) K P ​ / K C ​ is less than 1 Choose the option with the correct matching:

TestHub · Accepted Answer

K P ​ / K C ​ = ( RT ) Δ n with RT = 32.8 and ( RT ) 2 = 1076 . (P) Δ n = 4 − 2 = 2 : 1076 (2). (Q) Δ n = − 2 : 1/1076 = 9.3 × 1 0 − 4 (5), less than 1 (6). (R) Δ n = 3 − 2 = + 1 : 32.8 (1). (S) Δ n = 2 − 3 = − 1 : 1/32.8 = 0.0305 (4), less than 1 (6). Correct matching: P to 2; Q to 5,6; R to 1; S to 4,6. Answer: (D).

Column I (Reaction)	Column II (Statement)
(P) $2 N H_{3} (g) ⇌ N_{2} (g) + 3 H_{2} (g)$	(1) $K_{P} / K_{C} = 32.8$
(Q) $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$	(2) $K_{P} / K_{C}$ is about 1076
(R) $2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$	(3) $K_{P} / K_{C} = 1$
(S) $2 NO (g) + O_{2} (g) ⇌ 2 N O_{2} (g)$	(4) $K_{P} / K_{C}$ is about 0.0305
	(5) $K_{P} / K_{C}$ is about $9.3 \times 1 0^{- 4}$
	(6) $K_{P} / K_{C}$ is less than 1

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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