Equilibrium constant for the reaction 4 A ( g ) ⇌ B ( g ) + 2 C ( g ) is – Given: 2 A g ⇌ B g + Y g ; k c 1 = 8 C g ⇌ A g + 1 2 Y g ; k c 2 = 1 4

2 A g ⇌ B g + Y g k c 1 = 8 ……. (1) 2 A g + Y g ⇌ 2 C g k c 2 = ( 4 ) 2 = 16 ……. (2) Add equation (1) and (2) 4 A g + Y g ⇌ B g + 2 C g k C = k c 1 × k c 2 = 8 × 16 = 128

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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Equilibrium constant for the reaction $4 A (g) \overset{}{⇌} B (g) + 2 C (g)$ is –
Given:
$2 A (g) \overset{}{⇌} B (g) + Y (g); k c_{1} = 8$
$C (g) \overset{}{⇌} A (g) + \frac{1}{2} Y (g); k c_{2} = \frac{1}{4}$

Options:

Answer:

Solution:

$2 A (g) \overset{}{⇌} B (g) + Y (g) k c_{1} = 8$ ……. (1)
$2 A (g) + Y (g) \overset{}{⇌} 2 C (g) k c_{2} = (4)^{2} = 16$ ……. (2)
Add equation (1) and (2)
$4 A (g) + Y (g) \overset{}{⇌} B (g) + 2 C (g)$
$k_{C} = k c_{1} \times k c_{2} = 8 \times 16 = 128$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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