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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumProblems involving KcEasy2 minQB

ChemistryEasysingle choice

If the forward rate constant of a reversible reaction is 0.045 and the backward rate constant is $1.5 \times 1 0^{5}$ , then the equilibrium constant will be

Options:

Answer:

Solution:

K = $k f / kb = 0.045/ (1.5 \times 1 0^{5}) = 3 \times 1 0^{- 7}$ .

Trap: the product kfkb gives $6.75 \times 1 0^{3}$ .

Answer: (A).

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc

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