A mixture initially has reaction quotient Q = e 3 . Which pair gives the equilibrium constant and the initial direction of net reaction?

Equal pre-exponential factors give K = exp[-Δ H/(RT)]. K = exp[15962.88/(8.314×320)] = e 6 . Since Q = e 3 < e 6 = K, the net reaction initially proceeds forward. The required pair is option (b).

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ChemistryChemical EquilibriumProblems involving KcMedium2 minQB

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A mixture initially has reaction quotient Q = e³. Which pair gives the equilibrium constant and the initial direction of net reaction?

Options:

Answer:

Solution:

Equal pre-exponential factors give K = exp[-Δ H/(RT)]. K = exp[15962.88/(8.314×320)] = e⁶.

Since Q = e³ < e⁶ = K, the net reaction initially proceeds forward.

The required pair is option (b).

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc

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