For the reaction A 2 (g) + B 2 (g) ⇌ 2AB(g), 4 moles of A 2 was taken in a 2 L vessel and 3 moles of B 2 was taken in a 3 L vessel. Both vessels were then connected. At equilibrium the concentration o

Question

For the reaction A 2 (g) + B 2 (g) ⇌ 2AB(g), 4 moles of A 2 was taken in a 2 L vessel and 3 moles of B 2 was taken in a 3 L vessel. Both vessels were then connected. At equilibrium the concentration of AB is 0.8 M. Equilibrium concentrations of A 2 and B 2 would be

TestHub · Accepted Answer

Final volume = 2 + 3 = 5 L Initial [A 2 ] = 4/5 = 0.8 M and [B 2 ] = 3/5 = 0.6 M AB formed = 0.8 M, so each reactant falls by 0.8/2 = 0.4 M [A 2 ] = 0.8 - 0.4 = 0.4 M and [B 2 ] = 0.6 - 0.4 = 0.2 M This is option (b).

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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