Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumPhysical Equilibrium and Phase DiagramMedium2 minQB

ChemistryMediuminteger

$Zn (OH)_{2}$ is added to an acidic solution. What is the molar concentration of $Zn (OH)^{+}$ in the solution of $pH = 1$ at $2 5^{\circ} C$

Answer:

Solution:

Given $K_{1} = [Z n (O H)_{2}] = 1 0^{- 6} M$

Also $K_{2} = \frac{Zn ( OH ) ^{+} \times [ OH ^{-} ]}{Zn ( OH ) _{2}} = 1 0^{- 7}$

also $Kw = (H^{+}) (OH^{-}) = 1 0^{- 14}$ and $(H^{+}) = 1 0^{- 1} ∴ (O H^{-}) = 1 0^{- 13}$

$[Zn (OH)^{+}] = \frac{1 0 ^{- 7} \times 1 0 ^{- 6}}{1 0 ^{- 13}} = 1$

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Physical Equilibrium and Phase Diagram

⏱ 2mℹ️ Source: QB

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