Chemistry - Chemical Equilibrium Question with Solution | TestHub
\begin{gathered}{}\text{When}\text{ }\alpha\text{-D-glucose}\text{ }\text{is}\text{ }\text{dissolved}\text{ }\text{in}\text{ }\text{water,}\text{ }\text{it}\text{ }\text{undergoes}\text{ }\text{a}\text{ }\text{partial}\text{ }\text{conversion}\text{ }\text{to}\text{ }\\{}\beta\text{-D-glucose.}\text{ }\text{This}\text{ }\text{conversion,}\text{ }\text{called}\text{ }\text{mutarotation,}\text{ }\text{stops}\text{ }\text{when}\text{ }\text{64.0%}\text{ }\text{of}\text{ }\text{the}\text{ }\\{}\text{glucose}\text{ }\text{is}\text{ }\text{in}\text{ }\text{the}\text{ }\beta\text{-form.}\text{ }\text{Assuming}\text{ }\text{that}\text{ }\text{equilibrium}\text{ }\text{has}\text{ }\text{been}\text{ }\text{attained,}\text{ }\text{what}\text{ }\text{is}\text{ }\\{}\Delta\text{ }\text{G}^{{}^\circ}\text{ }\text{for}\text{ }\text{the}\text{ }\text{reaction:}\text{ }\alpha\text{-D-glucose}\text{ }\rightleftharpoons\text{ }\beta\text{-D-glucose,}\text{ }\text{at}\text{ }\text{this}\text{ }\text{experimental}\text{ }\\{}\text{temperature?}\end{gathered}
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Answer:
Solution:
\begin{gathered}{}\text{At}\text{ }\text{equilibrium}\text{ }\text{64%}\text{ }\text{is}\text{ }\beta\text{ }\text{and}\text{ }\text{36%}\text{ }\text{is}\text{ }\alpha\text{ }\text{K}\text{ }\text{=}\text{ }\text{[}\beta\text{]/[}\alpha\text{]}\text{ }\text{=}\text{ }\text{64/36}\text{ }\text{=}\text{ }\text{1.78}\\{}\Delta\text{ }\text{G}^{{}^\circ}\text{ }\text{=}\text{ }\text{-RTln}\text{ }\text{K}\text{ }\text{=}\text{ }\text{-RTln(1.78)}\\{}\text{This}\text{ }\text{is}\text{ }\text{option}\text{ }\text{(c).}\end{gathered}
