Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KcEasy2 minQB
ChemistryEasysingle choice
At a certain temperature, Kc = 1.2×10-3 for N2(g) + O2(g) ⇌ 2NO(g). Assuming a gas mixture of three volumes of nitrogen with one volume of oxygen, the percentage of nitric oxide by volume at equilibrium is approximately
Options:
Answer:
C
Solution:
Take 3 volumes of N2 and 1 volume of O2; x volumes of each react Kc = ((2x)2)/((3-x)(1-x)) = 1.2×10-3
Since x is small, 4x2 ≈ 1.2×10-3×3, so x ≈ 0.03
NO formed = 2x = 0.06 volumes out of a total of 4 volumes
Percentage of NO = 0.06/4×100 = 1.5%
This is option (c).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB
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