Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumDegree of Dissociation/Vapour Density/Molar MassEasy2 minQB
ChemistryEasysingle choice

Options:

Answer:
D
Solution:

\begin{gathered}{}\text{Molar}\text{ }\text{mass}\text{ }\text{of}\text{ }\text{PCl}_{\text{5}}\text{ }\text{=}\text{ }\text{208.5,}\text{ }\text{so}\text{ }\text{theoretical}\text{ }\text{vapour}\text{ }\text{density}\text{ }\text{D}\text{ }\text{=}\text{ }\text{104.25}\text{ }\text{Observed}\text{ }\\{}\text{vapour}\text{ }\text{density}\text{ }\text{d}\text{ }\text{=}\text{ }\text{62}\\{}\alpha\text{ }\text{=}\text{ }\text{(D-d)/(d(n-1))}\text{ }\text{=}\text{ }\text{(104.25-62)/(62}\times\text{1)}\\{}\alpha\text{ }\text{=}\text{ }\text{0.681,}\text{ }\text{so}\text{ }\text{dissociation}\text{ }\text{is}\text{ }\text{68.1%}\\{}\text{This}\text{ }\text{is}\text{ }\text{option}\text{ }\text{(d).}\end{gathered}

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Degree of Dissociation/Vapour Density/Molar Mass
⏱ 2mℹ️ Source: QB

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