Chemistry - Chemical Equilibrium Question with Solution | TestHub

$$\begin{array}{c}\text{First}\text{case:}\text{acid}\text{=}\text{1}\text{mol,}\text{alcohol}\text{=}\text{1}\text{mol,}\text{ester}\text{=}\text{44/88}\text{=}\text{0.5}\text{mol}\text{At}\\ \text{equilibrium}\text{acid}\text{=}\text{0.5,}\text{alcohol}\text{=}\text{0.5,}\text{ester}\text{=}\text{0.5,}\text{water}\text{=}\text{0.5}\text{mol;}\text{volume}\\ \text{cancels}\text{since}\Delta \text{n}\text{=}\text{0}\\ {\text{K}}_{\text{c}}\text{=}\text{((0.5)(0.5))/((0.5)(0.5))}\text{=}\text{1}\\ \text{Second}\text{case:}\text{acid}\text{=}\text{2}\text{mol,}\text{alcohol}\text{=}\text{1}\text{mol;}\text{ester}\text{formed}\text{=}\text{x}\text{mol}\\ {\text{x}}^{\text{2}}\text{/((2-x)(1-x))}\text{=}\text{1,}\text{so}{\text{x}}^{\text{2}}\text{=}\text{2}\text{-}\text{3x}\text{+}{\text{x}}^{\text{2}}\text{and}\text{x}\text{=}\text{2/3}\\ \text{Mass}\text{of}\text{ester}\text{=}\text{2/3}\times \text{88}\text{=}\text{58.67}\text{g}\\ \text{This}\text{is}\text{option}\text{(d).}\end{array}$$