Consider the reaction X 2 Y ( g ) = X 2 ( g ) + 2 1 Y 2 ( g ) The equation representing correct relationship between the degree of dissociation (x) of X 2 Y ( g ) with its equilibrium consta

Question

Consider the reaction X 2 ​ Y ( g ) = X 2 ​ ( g ) + 2 1 ​ Y 2 ​ ( g ) The equation representing correct relationship between the degree of dissociation (x) of X 2 ​ Y ( g ) with its equilibrium constant Kp is ______ . Assume x to be very very small.

TestHub · Accepted Answer

​ 1 mol X 2 ​ Y ( g ) → x X ​ X 2 ​ ( g ) + 2 1 ​ Y 2 ​ ( g ) 2 x ​ ∴ P x 2 ​ y ​ = 1 + 2 x ​ 1 − x ​ × p P x 2 ​ ​ = 1 + 2 x ​ x ​ × p ​ ∴ K p ​ = ∴ ​ P y 2 ​ ​ = 1 + 2 x ​ x /2 ​ × p ( 1 + 2 x ​ 1 − x ​ ) × p ( 1 + 2 x ​ x ​ p ) ( 2 ( 1 + 2 x ​ ) x ​ p ) 1/2 ​ K p ​ = ( 1 − x x ​ ) ( 2 ( 1 + 2 x ​ ) x ​ ) 1/2 × p 1/2 ​ ∴ x to be very small ∴ ∴ ​ K p ​ = 2 ( 1/2 ) x 3/2 ​ × p 1/2 x 3/2 = p 1/2 K p ​ × 2 1/2 ​ x 3 = p K p 2 ​ × 2 ​ x = ( p K p 2 ​ × 2 ​ ) 1/3 ​

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