The equilibrium constant for the reaction $A (s) ⇌ M (s) + \frac{1}{2} O_{2} (g)$ is $K_{p} = 4 .$ At equilibrium, the partial pressure of $O_{2}$ is _____ atm. (Round off to the nearest integer)
Answer:
16.00
Solution:
$K_{p} = P_{O_{2}}^{1 / 2} = 4$
$∴ P_{O_{2}} = 16 atm$

Question

The equilibrium constant for the reaction A ( s ) ⇌ M ( s ) + 1 2 O 2 ( g ) is K p = 4 . At equilibrium, the partial pressure of O 2 is _____ atm. (Round off to the nearest integer)

TestHub · Accepted Answer

K p = P O 2 1 / 2 = 4 ∴ P O 2 = 16 atm

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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