Consider the following reactions in which all the reactants and the products are in gaseous state.
$2PQ ⇌ P_{2} + Q_{2}; K_{1} = 3.6 \times 1 0^{5}$
$PQ + 1 / 2 R_{2} ⇌ PQR; K_{2} = 6 \times 1 0^{- 3}$
The value of $K_{3}$ for the equilibrium
$1 / 2 P_{2} + 1 / 2 Q_{2} + 1 / 2 R_{2} ⇌ PQR$ is

Question

TestHub · Accepted Answer

Given , 2PQ ⇌ P 2 + Q 2 K 1 = P 2 Q 2 [ P Q ] 2 = 3.6 × 1 0 5 PQ + 1 / 2 R 2 ⇌ PQR ; K 2 = [ PQR ] PQ R 2 1 / 2 = 6 × 1 0 - 3 For the required equilibrium 1 / 2 P 2 + 1 / 2 Q 2 + 1 / 2 R 2 ⇌ PQR ; K 3 = [ PQR ] P 2 1 / 2 Q 2 1 / 2 R 2 1 / 2 K 3 = K 2 × 1 K 1 = 6 × 1 0 - 3 × 1 3.6 × 1 0 5 = 6 × 1 0 - 3 0.6 × 1 0 3 = 1 × 1 0 - 5

Chemistry - Chemical Equilibrium Question with Solution | TestHub

Options:

Doubts & Discussion