XY 2 dissociates as XY 2 ( g ) ⇌ XY ( g ) + Y ( g ) . Initial pressure of XY 2 is 600 mm Hg . The total pressure at equilibrium is 800 mm Hg . Assuming volume of system to remain constant the va

Question

XY 2 ​ dissociates as XY 2 ​ ( g ) ⇌ XY ( g ) + Y ( g ) . Initial pressure of XY 2 ​ is 600 mm Hg . The total pressure at equilibrium is 800 mm Hg . Assuming volume of system to remain constant the value of K p ​ in mm Hg is

TestHub · Accepted Answer

X Y 2 ​ ( g ) ⇌ X Y ( g ) + Y ( g ) , pressures in mm at t = 0 600 0 0 pressures in mm at equilib., ( 600 − x ) x x Total pressure at equilibrium = 800 mm. 600 + x = 800 x = 200 mm K p ​ = P X Y 2 ​ ​ P X Y ​ ⋅ P Y ​ ​ K p ​ = 400 200 ⋅ 200 ​ = 400 40000 ​ = 100 mm

Chemistry - Chemical Equilibrium Question with Solution | TestHub

Options:

Doubts & Discussion