The equilibrium constant for the disproportionation of $H g C l_{2}$ into $H g C l^{+}$ and $H g C l_{3}^{-}$ is
Given ${HgCl}^{+} + {Cl}^{-} ⇌ {HgCl}_{2}; K_{1} = 3 \times 10^{6}$
$H g C l_{2} + C l^{-} ⇌ H g C l_{3}^{-}; K_{2} = 9.0$

Question

The equilibrium constant for the disproportionation of H g C l 2 into H g C l + and H g C l 3 - is Given HgCl + + Cl − ⇌ HgCl 2 ; K 1 = 3 × 10 6 H g C l 2 + C l - ⇌ H g C l 3 - ; K 2 = 9.0

TestHub · Accepted Answer

K 1 = [ H g C l 2 ] [ H g C l + ] [ C l - ] ; K 2 = [ H g C l 3 - ] [ H g C l 2 ] [ C l - ] So K 3 = [ H g C l + ] [ H g C l 3 - ] [ H g C l 2 ] 2 = K 2 K 1 = 9 3 × 1 0 6 = 3 × 1 0 - 6

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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